Which one of the following will be the output | vedclass

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(D) Let the inputs be $A$ and $B$. $1$. The upper branch consists of an $AND$ gate followed by a $NOT$ gate,which is a $NAND$ gate. Its output is $\ov

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$XOR$ Gate

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(D) Let the inputs be $A$ and $B$. $1$. The upper branch consists of an $AND$ gate followed by a $NOT$ gate,which is a $NAND$ gate. Its output is $\overline{A \cdot B}$. $2$. The lower branch is an $OR$ gate. Its output is $(A + B)$. $3$. These two outputs are fed into a final $AND$ gate. $4$. The final output $Y = \overline{A \cdot B} \cdot (A + B)$. $5$. Using Boolean algebra: $Y = (\overline{A} + \overline{B}) \cdot (A + B) = \overline{A}A + \overline{A}B + \overline{B}A + \overline{B}B$. $6$. Since $\overline{A}A = 0$ and $\overline{B}B = 0$,we get $Y = \overline{A}B + A\overline{B}$. $7$. This is the Boolean expression for an $XOR$ gate.

Which one of the following will be the output of the given circuit?

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